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THE EXPONENTIAL AND LOGARITHMIC FUNCTIONS


Exponents. The process of defining the meaning of an is a multi-step process.


 Step 1. Define the meaning of the symbol an where a is any real number and n is a positive integer as follows:


            a1 = a

            a2 = a • a

            a3 = a • a • a

            .....

            an = a • a • a .... to n factors


This gives us a meaning for an when the exponent n is a positive integer. The following laws are valid for an defined as above (m and n are positive integers):


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ole1.gif


ole2.gif


ole3.gif


ole4.gif  


Next we want to give a meaning to such symbols as


             ole5.gif


Our object will be to define these symbols in such a way that laws 1 through 5 will apply in all cases.



Step 2. Assign a meaning to a0. If we want Law 1 to hold so that


 

             ole6.gif


we must assign the value one to the symbol a0.


Def. a0 = 1.



Step 3. Assign a meaning to negative integral exponents. If we wish Law 1 to hold so that

 

            am • a - m = am - m = a0 = 1           (m is an integer, a≠0)


we must agree that a - m = 1/am.


Def. a-m = 1/am where m is an integer.



Def. n-th root. If an = p, where n is a positive integer, we call a an n-th root of p, written ole7.gif There may be more than one real n-th root of p. For example since 22 = 4 and (-2)2 = 4, there are two real square roots of 4, namely 2 and -2.



Step 4. Assign a meaning to fractional exponents. If we wish Law 1 to hold so that


             ole8.gif


we must define the symbol a½ to stand for a square root of a. To avoid ambiguity we can define it to stand for the positive square root. In general, we define the symbol


              ole9.gif  


to stand for the positive q-th root of a.


ole10.gif  



ole11.gif



It follows from these definitions that


             ole12.gif


and that the above five laws are valid if m and n are either fractions or integers (i.e. if they are rational numbers), provided a and b are positive numbers. If the exponent is irrational, the power is defined to be the quantity approximated by using rational exponents which approximate the irrational exponent; e.g. 3 with exponent ole13.gif denotes the limit of the sequence


             ole14.gif



Three important limits.


Theorem 1. If θ is in radians, then


             ole15.gif


Theorem 2. If θ is in radians, then


             ole16.gif


Theorem 3. The number e is given by


             ole17.gif


Logarithms to the base e are called natural logarithms. Loge x is often called log x (base omitted) or ln x.





Def. Exponential function. (1) The function ex.

(2) The function ax, where a is a positive constant. If a ole18.gif 1, the function ax is the inverse of the logarithmic function logax.

                                                James & James. Mathematics Dictionary.


ole19.gif

The exponential function y = ax is shown in Fig. 1. Its derivative is everywhere positive and increases with increasing values of x.

                                                                                                


Def. Logarithmic function y = loga x (a > 1). The logarithmic function is defined as the inverse of the exponential function i.e. if


            x = ay 

                                                                                                

ole20.gif

then


            y = loga x .



See Fig. 2. Its graph is the same as that of y = ax with the axes interchanged. It is defined only for positive values of x.







RULES OF EXPONENTS AND LOGARITHMS


Let a, b, p, q be any real numbers.


Rules of exponents.


ole21.gif


ole22.gif


ole23.gif


ole24.gif


ole25.gif


ole26.gif


ole27.gif


ole28.gif  


ole29.gif






Laws of logarithms.


ole30.gif


ole31.gif  


ole32.gif


ole33.gif


ole34.gif


ole35.gif


ole36.gif


Change of base:

ole37.gif


ole38.gif


ole39.gif






________________________________________________________


Prove.


             ole40.gif


Proof. Let


(1)       x = logb N


or, equivalently,


(2)       bx = N.


Taking loga of both sides of (2), we have


(3)       x loga b = loga N


or


ole41.gif


From (1) and (4) we get


ole42.gif



End of Proof.





Prove.


             ole43.gif



Proof. Taking N = a and substituting into (5) we get



ole44.gif


and since loga a = 1, (6) becomes


             ole45.gif



End of Proof.



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